Optimal. Leaf size=130 \[ -\frac{b^2 \text{PolyLog}\left (2,1-\frac{2}{1-c x}\right )}{3 c^3}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{3 c^3}-\frac{2 b \log \left (\frac{2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{3 c^3}+\frac{1}{3} x^3 \left (a+b \tanh ^{-1}(c x)\right )^2+\frac{b x^2 \left (a+b \tanh ^{-1}(c x)\right )}{3 c}+\frac{b^2 x}{3 c^2}-\frac{b^2 \tanh ^{-1}(c x)}{3 c^3} \]
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Rubi [A] time = 0.200816, antiderivative size = 130, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.571, Rules used = {5916, 5980, 321, 206, 5984, 5918, 2402, 2315} \[ -\frac{b^2 \text{PolyLog}\left (2,1-\frac{2}{1-c x}\right )}{3 c^3}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{3 c^3}-\frac{2 b \log \left (\frac{2}{1-c x}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{3 c^3}+\frac{1}{3} x^3 \left (a+b \tanh ^{-1}(c x)\right )^2+\frac{b x^2 \left (a+b \tanh ^{-1}(c x)\right )}{3 c}+\frac{b^2 x}{3 c^2}-\frac{b^2 \tanh ^{-1}(c x)}{3 c^3} \]
Antiderivative was successfully verified.
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Rule 5916
Rule 5980
Rule 321
Rule 206
Rule 5984
Rule 5918
Rule 2402
Rule 2315
Rubi steps
\begin{align*} \int x^2 \left (a+b \tanh ^{-1}(c x)\right )^2 \, dx &=\frac{1}{3} x^3 \left (a+b \tanh ^{-1}(c x)\right )^2-\frac{1}{3} (2 b c) \int \frac{x^3 \left (a+b \tanh ^{-1}(c x)\right )}{1-c^2 x^2} \, dx\\ &=\frac{1}{3} x^3 \left (a+b \tanh ^{-1}(c x)\right )^2+\frac{(2 b) \int x \left (a+b \tanh ^{-1}(c x)\right ) \, dx}{3 c}-\frac{(2 b) \int \frac{x \left (a+b \tanh ^{-1}(c x)\right )}{1-c^2 x^2} \, dx}{3 c}\\ &=\frac{b x^2 \left (a+b \tanh ^{-1}(c x)\right )}{3 c}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{3 c^3}+\frac{1}{3} x^3 \left (a+b \tanh ^{-1}(c x)\right )^2-\frac{1}{3} b^2 \int \frac{x^2}{1-c^2 x^2} \, dx-\frac{(2 b) \int \frac{a+b \tanh ^{-1}(c x)}{1-c x} \, dx}{3 c^2}\\ &=\frac{b^2 x}{3 c^2}+\frac{b x^2 \left (a+b \tanh ^{-1}(c x)\right )}{3 c}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{3 c^3}+\frac{1}{3} x^3 \left (a+b \tanh ^{-1}(c x)\right )^2-\frac{2 b \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2}{1-c x}\right )}{3 c^3}-\frac{b^2 \int \frac{1}{1-c^2 x^2} \, dx}{3 c^2}+\frac{\left (2 b^2\right ) \int \frac{\log \left (\frac{2}{1-c x}\right )}{1-c^2 x^2} \, dx}{3 c^2}\\ &=\frac{b^2 x}{3 c^2}-\frac{b^2 \tanh ^{-1}(c x)}{3 c^3}+\frac{b x^2 \left (a+b \tanh ^{-1}(c x)\right )}{3 c}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{3 c^3}+\frac{1}{3} x^3 \left (a+b \tanh ^{-1}(c x)\right )^2-\frac{2 b \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2}{1-c x}\right )}{3 c^3}-\frac{\left (2 b^2\right ) \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1-c x}\right )}{3 c^3}\\ &=\frac{b^2 x}{3 c^2}-\frac{b^2 \tanh ^{-1}(c x)}{3 c^3}+\frac{b x^2 \left (a+b \tanh ^{-1}(c x)\right )}{3 c}+\frac{\left (a+b \tanh ^{-1}(c x)\right )^2}{3 c^3}+\frac{1}{3} x^3 \left (a+b \tanh ^{-1}(c x)\right )^2-\frac{2 b \left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2}{1-c x}\right )}{3 c^3}-\frac{b^2 \text{Li}_2\left (1-\frac{2}{1-c x}\right )}{3 c^3}\\ \end{align*}
Mathematica [A] time = 0.257234, size = 122, normalized size = 0.94 \[ \frac{b^2 \text{PolyLog}\left (2,-e^{-2 \tanh ^{-1}(c x)}\right )+a^2 c^3 x^3+a b c^2 x^2+a b \log \left (c^2 x^2-1\right )+b \tanh ^{-1}(c x) \left (2 a c^3 x^3+b c^2 x^2-2 b \log \left (e^{-2 \tanh ^{-1}(c x)}+1\right )-b\right )+b^2 \left (c^3 x^3-1\right ) \tanh ^{-1}(c x)^2+b^2 c x}{3 c^3} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.013, size = 270, normalized size = 2.1 \begin{align*}{\frac{{x}^{3}{a}^{2}}{3}}+{\frac{{b}^{2}{x}^{3} \left ({\it Artanh} \left ( cx \right ) \right ) ^{2}}{3}}+{\frac{{b}^{2}{\it Artanh} \left ( cx \right ){x}^{2}}{3\,c}}+{\frac{{b}^{2}{\it Artanh} \left ( cx \right ) \ln \left ( cx-1 \right ) }{3\,{c}^{3}}}+{\frac{{b}^{2}{\it Artanh} \left ( cx \right ) \ln \left ( cx+1 \right ) }{3\,{c}^{3}}}+{\frac{{b}^{2}x}{3\,{c}^{2}}}+{\frac{{b}^{2}\ln \left ( cx-1 \right ) }{6\,{c}^{3}}}-{\frac{{b}^{2}\ln \left ( cx+1 \right ) }{6\,{c}^{3}}}+{\frac{{b}^{2} \left ( \ln \left ( cx-1 \right ) \right ) ^{2}}{12\,{c}^{3}}}-{\frac{{b}^{2}}{3\,{c}^{3}}{\it dilog} \left ({\frac{1}{2}}+{\frac{cx}{2}} \right ) }-{\frac{{b}^{2}\ln \left ( cx-1 \right ) }{6\,{c}^{3}}\ln \left ({\frac{1}{2}}+{\frac{cx}{2}} \right ) }-{\frac{{b}^{2}}{6\,{c}^{3}}\ln \left ( -{\frac{cx}{2}}+{\frac{1}{2}} \right ) \ln \left ({\frac{1}{2}}+{\frac{cx}{2}} \right ) }+{\frac{{b}^{2}\ln \left ( cx+1 \right ) }{6\,{c}^{3}}\ln \left ( -{\frac{cx}{2}}+{\frac{1}{2}} \right ) }-{\frac{{b}^{2} \left ( \ln \left ( cx+1 \right ) \right ) ^{2}}{12\,{c}^{3}}}+{\frac{2\,ab{x}^{3}{\it Artanh} \left ( cx \right ) }{3}}+{\frac{ab{x}^{2}}{3\,c}}+{\frac{ab\ln \left ( cx-1 \right ) }{3\,{c}^{3}}}+{\frac{ab\ln \left ( cx+1 \right ) }{3\,{c}^{3}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{3} \, a^{2} x^{3} + \frac{1}{3} \,{\left (2 \, x^{3} \operatorname{artanh}\left (c x\right ) + c{\left (\frac{x^{2}}{c^{2}} + \frac{\log \left (c^{2} x^{2} - 1\right )}{c^{4}}\right )}\right )} a b - \frac{1}{216} \,{\left (2 \, c^{4}{\left (\frac{2 \,{\left (c^{2} x^{3} + 3 \, x\right )}}{c^{6}} - \frac{3 \, \log \left (c x + 1\right )}{c^{7}} + \frac{3 \, \log \left (c x - 1\right )}{c^{7}}\right )} - 3 \, c^{3}{\left (\frac{x^{2}}{c^{4}} + \frac{\log \left (c^{2} x^{2} - 1\right )}{c^{6}}\right )} - 648 \, c^{3} \int \frac{x^{3} \log \left (c x + 1\right )}{9 \,{\left (c^{4} x^{2} - c^{2}\right )}}\,{d x} + 9 \, c^{2}{\left (\frac{2 \, x}{c^{4}} - \frac{\log \left (c x + 1\right )}{c^{5}} + \frac{\log \left (c x - 1\right )}{c^{5}}\right )} - 324 \, c \int \frac{x \log \left (c x + 1\right )}{9 \,{\left (c^{4} x^{2} - c^{2}\right )}}\,{d x} - \frac{6 \,{\left (3 \, c^{3} x^{3} \log \left (c x + 1\right )^{2} +{\left (2 \, c^{3} x^{3} - 3 \, c^{2} x^{2} + 6 \, c x - 6 \,{\left (c^{3} x^{3} + 1\right )} \log \left (c x + 1\right )\right )} \log \left (-c x + 1\right )\right )}}{c^{3}} - \frac{2 \,{\left (c x - 1\right )}^{3}{\left (9 \, \log \left (-c x + 1\right )^{2} - 6 \, \log \left (-c x + 1\right ) + 2\right )} + 27 \,{\left (c x - 1\right )}^{2}{\left (2 \, \log \left (-c x + 1\right )^{2} - 2 \, \log \left (-c x + 1\right ) + 1\right )} + 54 \,{\left (c x - 1\right )}{\left (\log \left (-c x + 1\right )^{2} - 2 \, \log \left (-c x + 1\right ) + 2\right )}}{c^{3}} + \frac{18 \, \log \left (9 \, c^{4} x^{2} - 9 \, c^{2}\right )}{c^{3}} - 324 \, \int \frac{\log \left (c x + 1\right )}{9 \,{\left (c^{4} x^{2} - c^{2}\right )}}\,{d x}\right )} b^{2} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (b^{2} x^{2} \operatorname{artanh}\left (c x\right )^{2} + 2 \, a b x^{2} \operatorname{artanh}\left (c x\right ) + a^{2} x^{2}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int x^{2} \left (a + b \operatorname{atanh}{\left (c x \right )}\right )^{2}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (b \operatorname{artanh}\left (c x\right ) + a\right )}^{2} x^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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